Number System - An Introduction
Choose the correct option
Question 1
In a decimal number system, the base of a number is represented by
- 2
- 10
- 16
- All of them
Answer
10
Reason — The decimal number system uses 10 digits (from 0 to 9) hence its has a base of 10.
Question 2
The base of an octal number is represented by:
- 2
- 8
- 7
- None
Answer
8
Reason — The octal number system uses 8 digits (from 0 to 7) hence its has a base of 8.
Question 3
To convert an octal number to its binary equivalent, each octal digit is expressed as
- 3 bits form
- 4 bits form
- 8 bits form
- All of them
Answer
3 bits form
Reason — Since the digits from 0 to 7 need a maximum of 3 bits to be represented in binary form hence in Octal to Binary conversion each octal digit is expressed as 3 bits form.
Question 4
Sixteen raised to the power zero (16⁰) is equivalent to
- 0
- 1
- 0 and 1
- None
Answer
1
Reason — Any number raised to the power of 0 is 1.
Question 5
An octal number system uses the digits from
- 0 to 8
- 1 to 8
- 0 to 7
- All of them
Answer
0 to 7
Reason — The octal number system is a base 8 number system as it uses the digits from 0 to 7.
Question 6
The base of a hexa-decimal number is represented by
- H16
- 16
- 15
- None
Answer
16
Reason — The hexa-decimal number system uses 16 digits (from 0 to 15) hence its has a base of 16.
Question 7
In a hexa-decimal number system, 'B' represents the digit
- 11
- 12
- 14
- 13
Answer
11
Reason — In hexa-decimal number system, the digits 0 to 15 are represented by the letters A to F.
Question 8
To express a hexa-decimal number to its binary equivalent, each hexa-decimal digit is expressed as
- 2 bits form
- 3 bits form
- 4 bits form
- None
Answer
4 bits form
Reason — Since the digits from 0 to 15 need a maximum of 4 bits to be represented in binary form hence in Hexa-decimal to Binary conversion each hexa-decimal digit is expressed as 4 bits form.
Question 9
The binary equivalent of a hexa-decimal digit 12(C) is represented by
- 1010
- 1011
- 1101
- 1100
Answer
1100
Reason — The hexa-decimal digit 12(C) is represented as 1100.
Question 10
The hexa-decimal equivalent digit of 1011 (4 bits form) is
- 14
- 15
- 11
- 12
Answer
11
Reason — The hexa-decimal equivalent digit of 1011 (4 bits form) is 11.
Fill in the blanks
Question 1
The binary system consists of two digits 0 and 1.
Question 2
A decimal number system uses the digits from 0 to 9.
Question 3
The base in the decimal number system is written as 10.
Question 4
A binary number system is written with 2 as the base.
Question 5
In a decimal to binary conversion, the first remainder is known as Least Significant Bit (LSB) and the last remainder is Most Significant Bit (MSB).
Question 6
20 = 1
Complete the following tables
Octal Digit | Binary Equivalent |
---|---|
5 | |
7 | |
1 | |
6 | |
3 |
Hexadecimal Digit | Binary Equivalent |
---|---|
8 | |
11 | |
4 | |
15 | |
9 |
Answer
Octal Digit | Binary Equivalent |
---|---|
5 | 101 |
7 | 111 |
1 | 001 |
6 | 110 |
3 | 011 |
Hexadecimal Digit | Binary Equivalent |
---|---|
8 | 1000 |
11 | 1011 |
4 | 0100 |
15 | 1111 |
9 | 1001 |
Case-Study Based Questions
Question 1
Your teacher has assigned you a task to give a presentation on conversion of octal numbers into binary numbers and vice-versa. You are asked to create some aids to support your presentation. You have created two tables, Table 1 and Table 2, to demonstrate some examples.
Octal Number | Binary Equivalent |
---|---|
1 | 001 |
5 | ....... |
3 | 010 |
6 | 110 |
Binary Number | Octal Equivalent |
---|---|
100 | ....... |
111 | 7 |
011 | 2 |
001110 | 16 |
In the above tables, some entries have either been missed or incorrect. Answer the following questions based on the above case:
(a) What will be filled in the blank space of Table 1?
(b) Find and rectify the incorrect binary equivalent in Table 1.
(c) Fill the appropriate octal equivalent in the blank space of Table 2.
(d) Find and rectify the incorrect octal equivalent in Table 2.
Answer
(a) 101
(b) In Table 1, the binary equivalent of octal number 3 is incorrect. The correct value is 011.
(c) 4
(d) In Table 2, the octal equivalent of binary number 011 is incorrect. The correct value is 3.
Convert the following to their binary equivalents
Question 1
(78)10
Answer
2 | Quotient | Remainder |
---|---|---|
2 | 78 | 0 (LSB) |
2 | 39 | 1 |
2 | 19 | 1 |
2 | 9 | 1 |
2 | 4 | 0 |
2 | 2 | 0 |
2 | 1 | 1 (MSB) |
0 |
Therefore, (78)10 = (1001110)2
Question 2
(99)10
Answer
2 | Quotient | Remainder |
---|---|---|
2 | 99 | 1 (LSB) |
2 | 49 | 1 |
2 | 24 | 0 |
2 | 12 | 0 |
2 | 6 | 0 |
2 | 3 | 1 |
2 | 1 | 1 (MSB) |
0 |
Therefore, (99)10 = (1100011)2
Question 3
(141)10
Answer
2 | Quotient | Remainder |
---|---|---|
2 | 141 | 1 (LSB) |
2 | 70 | 0 |
2 | 35 | 1 |
2 | 17 | 1 |
2 | 8 | 0 |
2 | 4 | 0 |
2 | 2 | 0 |
2 | 1 | 1 (MSB) |
0 |
Therefore, (141)10 = (10001101)2
Question 4
(123)10
Answer
2 | Quotient | Remainder |
---|---|---|
2 | 123 | 1 (LSB) |
2 | 61 | 1 |
2 | 30 | 0 |
2 | 15 | 1 |
2 | 7 | 1 |
2 | 3 | 1 |
2 | 1 | 1 (MSB) |
0 |
Therefore, (123)10 = (1111011)2
Convert the following to their decimal equivalents
Question 1
(10101)2
Answer
Binary No | Power | Value | Result |
---|---|---|---|
1 (LSB) | 20 | 1 | 1x1=1 |
0 | 21 | 2 | 0x2=0 |
1 | 22 | 4 | 1x4=4 |
0 | 23 | 8 | 0x8=0 |
1 (MSB) | 24 | 16 | 1x16=16 |
Equivalent decimal number = 1 + 4 + 16 = 21
Therefore, (10101)2 = (21)10
Question 2
(10000)2
Answer
Binary No | Power | Value | Result |
---|---|---|---|
0 (LSB) | 20 | 1 | 0x1=0 |
0 | 21 | 2 | 0x2=0 |
0 | 22 | 4 | 1x4=4 |
0 | 23 | 8 | 0x8=0 |
1 (MSB) | 24 | 16 | 1x16=16 |
Equivalent decimal number = 16
Therefore, (10000)2 = (16)10
Question 3
(11001)2
Answer
Binary No | Power | Value | Result |
---|---|---|---|
1 (LSB) | 20 | 1 | 1x1=1 |
0 | 21 | 2 | 0x2=0 |
0 | 22 | 4 | 0x4=0 |
1 | 23 | 8 | 1x8=8 |
1 (MSB) | 24 | 16 | 1x16=16 |
Equivalent decimal number = 1 + 8 + 16 = 25
Therefore, (11001)2 = (25)10
Question 4
(101010)2
Answer
Binary No | Power | Value | Result |
---|---|---|---|
0 (LSB) | 20 | 1 | 0x1=0 |
1 | 21 | 2 | 1x2=2 |
0 | 22 | 4 | 0x4=0 |
1 | 23 | 8 | 1x8=8 |
0 | 24 | 16 | 0x16=0 |
1 (MSB) | 25 | 32 | 1x32=32 |
Equivalent decimal number = 2 + 8 + 32 = 42
Therefore, (101010)2 = (42)10
Convert the following to Decimal numbers
Question 1
(510)8
Answer
Octal No | Power | Value | Result |
---|---|---|---|
0 (LSB) | 80 | 1 | 0x1=0 |
1 | 81 | 8 | 1x8=8 |
5 (MSB) | 82 | 64 | 5x64=320 |
Equivalent decimal number = 8 + 320 = 328
Therefore, (510)8 = (328)10
Question 2
(ABC)16
Answer
Hexadecimal Number | Power | Value | Result |
---|---|---|---|
C (12) | 160 | 1 | 12x1=12 |
B (11) | 161 | 16 | 11x16=176 |
A (10) | 162 | 256 | 10x256=2560 |
Equivalent decimal number = 12 + 176 + 2560 = 2748
Therefore, (ABC)16 = (2748)10
Question 3
(1001011)2
Answer
Binary No | Power | Value | Result |
---|---|---|---|
1 (LSB) | 20 | 1 | 1x1=1 |
1 | 21 | 2 | 1x2=2 |
0 | 22 | 4 | 0x4=0 |
1 | 23 | 8 | 1x8=8 |
0 | 24 | 16 | 0x16=0 |
0 | 25 | 32 | 0x32=0 |
1 (MSB) | 26 | 64 | 1x64=64 |
Equivalent decimal number = 1 + 2 + 8 + 64 = 75
Therefore, (1001011)2 = (75)10
Question 4
(CD7)16
Answer
Hexadecimal Number | Power | Value | Result |
---|---|---|---|
7 | 160 | 1 | 7x1=7 |
D (13) | 161 | 16 | 13x16=208 |
C (12) | 162 | 256 | 12x256=3072 |
Equivalent decimal number = 7 + 208 + 3072 = 3287
Therefore, (CD7)16 = (3287)10
Question 5
(101001)2
Answer
Binary No | Power | Value | Result |
---|---|---|---|
1 (LSB) | 20 | 1 | 1x1=1 |
0 | 21 | 2 | 0x2=0 |
0 | 22 | 4 | 0x4=0 |
1 | 23 | 8 | 1x8=8 |
0 | 24 | 16 | 0x16=0 |
1 (MSB) | 25 | 32 | 1x32=32 |
Equivalent decimal number = 1 + 8 + 32 = 41
Therefore, (101001)2 = (41)10
Question 6
(1100111)2
Answer
Binary No | Power | Value | Result |
---|---|---|---|
1 (LSB) | 20 | 1 | 1x1=1 |
1 | 21 | 2 | 1x2=2 |
1 | 22 | 4 | 1x4=4 |
0 | 23 | 8 | 0x8=0 |
0 | 24 | 16 | 0x16=0 |
1 | 25 | 32 | 1x32=32 |
1 (MSB) | 26 | 64 | 1x64=64 |
Equivalent decimal number = 1 + 2 + 4 + 32 + 64 = 103
Therefore, (1100111)2 = (103)10
Convert the following to binary numbers
Question 1
(342)8
Answer
Octal Number | Binary Equivalent |
---|---|
2 | 010 |
4 | 100 |
3 | 011 |
Therefore, (342)8 = ()2
Question 2
(203)8
Answer
Octal Number | Binary Equivalent |
---|---|
3 | 011 |
0 | 000 |
2 | 010 |
Therefore, (203)8 = ()2
Question 3
(9AD)16
Answer
Hexadecimal Number | Binary Equivalent |
---|---|
D (13) | 1101 |
A (10) | 1010 |
9 | 1001 |
Therefore, (9AD)16 = ()2
Question 4
(157)8
Answer
Octal Number | Binary Equivalent |
---|---|
7 | 111 |
5 | 101 |
1 | 001 |
Therefore, (157)8 = ()2
Question 5
(ABC)16
Answer
Hexadecimal Number | Binary Equivalent |
---|---|
C (12) | 1100 |
B (11) | 1011 |
A (10) | 1010 |
Therefore, (ABC)16 = ()2
Question 6
(DE)16
Answer
Hexadecimal Number | Binary Equivalent |
---|---|
E (14) | 1110 |
D (13) | 1101 |
Therefore, (DE)16 = ()2
Convert the following to their hexa-decimal equivalent
Question 1
(110011101111)2
Answer
Grouping in bits of 4:
Binary Number | Equivalent Hexadecimal |
---|---|
1111 | F (15) |
1110 | E (14) |
1100 | C (12) |
Therefore, (110011101111)2 = (CEF)16
Question 2
(11010111100)2
Answer
Grouping in bits of 4:
Binary Number | Equivalent Hexadecimal |
---|---|
1100 | C (12) |
1011 | B (11) |
0110 | 6 |
Therefore, (11010111100)2 = (6BC)16
Question 3
(89392)10
Answer
16 | Quotient | Remainder |
---|---|---|
16 | 89392 | 0 |
16 | 5587 | 3 |
16 | 349 | D (13) |
16 | 21 | 5 |
16 | 1 | 1 |
0 |
Therefore, (89392)10 = (15D30)16
Question 4
(100101101110)2
Answer
Grouping in bits of 4:
Binary Number | Equivalent Hexadecimal |
---|---|
1110 | E (14) |
0110 | 6 |
1001 | 9 |
Therefore, (100101101110)2 = (96E)16
Question 5
(9894)10
Answer
16 | Quotient | Remainder |
---|---|---|
16 | 9894 | 6 |
16 | 618 | A (10) |
16 | 38 | 6 |
16 | 2 | 2 |
0 |
Therefore, (9894)10 = (26A6)16
Question 6
(4966)10
Answer
16 | Quotient | Remainder |
---|---|---|
16 | 4966 | 6 |
16 | 310 | 6 |
16 | 19 | 3 |
16 | 1 | 1 |
0 |
Therefore, (4966)10 = (1366)16
Short Answer Questions
Question 1
What are the different types of number systems that a computer deals with?
Answer
The different types of number systems are:
- Binary Number System
- Octal Number System
- Decimal Number System
- Hexadecimal Number System
Question 2
What is meant by the following terms? Give an example of each.
(a) An octal number
(b) A hexa-decimal number
Answer
(a) An Octal number — An octal number uses 8 types of digits — 0, 1, 2, 3, 4, 5, 6, 7. It is represented with base 8.
(b) A hexa-decimal number — A Hexa-decimal number uses 16 types of digits (0 to 15). To represent digits from 10 to 15 it uses letters from A to F respectively. It is represented with base 16.
Question 3a
Give two differences between Binary number and Decimal number
Answer
Binary number | Decimal number |
---|---|
It uses 2 digits — 0 and 1. | It uses 10 digits — 0 to 9. |
It uses base 2. | It uses base 10. |
Question 3b
Give two differences between Octal number and Binary number
Answer
Octal number | Binary number |
---|---|
It uses 8 digits — 0 to 7. | It uses 2 digits — 0 and 1. |
It uses base 8. | It uses base 2. |